Question

The most probable velocity of a gas is proportional to
(A) T
(B) VT
IC 12
(D) 13/2​

Answer 1

$\mathfrak{ \huge{ \red{ \underline{ \underline{Answer}}}}}$

=> The most probable velocity(Vmp) of a gas molecule is given by...

$\: \: \: \: \: \green{ \huge{ \star}} \: \: \boxed{ \huge \pink{Vmp = \sqrt{ \frac{2 \times Kb \times T}{m} } }} \: \: \green {\huge{ \star}}$

=> here, Kb = boltzman constant

T = trmperature

m = mass of a single molecule

=> as per the given formula it is clear that

$\orange{ \huge{\implies}} \: \: \boxed{ \boxed{ \blue{ \bold{ \huge{ \underline{ \mathfrak{Vmp \propto \: \sqrt{T}}}}}}}}$