Question

The motion of a particle along a straight line described by the equation x=6+4t^2-t^4 Where x is in metres(m) and t is the positive time in seconds(s). Find the position, velocity and acceleration at t=2s. During what time interval is the velocity positive During what time interval is x positive What is the maximum possible velocity attained by the particle

Answer 1

Answer:

X=6

Explanation:

PUT , the value X=2

X=6+4(2)^2-(2)^4

X=6+16-16 [6+4×4-2×2×2×2]

X=6+0

X=6

Answer 2

Answer:

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