Question

The motion of a particle is described by equation x=20+4t2 where x is in metre and T sec . The average velocity of the partical in the time interval between t1=2 sec and t2=5sec

Answer 1

Answer:

a=15cms−1b=3cms−2

x=at+bt2

dtdx=v=a+2bt∣t=3

       =15+2×3×3

       =15+18

  V=33cm/s

Explanation:

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