Question

the motion of a particle is given by a=6v^1/2 where a is in m/sec^2 and v is in m/sec,when t=0 and v=0.find the relationbetween v and t

Answer 1

v=9t² v=0,t=0
use this relation
pls mark as brainliest

Answer 2

The relation between velocity and time for the given particle motion is v = 2t^3

Given: The motion of a particle is given by a = 6v^(1/2), where a is in m/s^2 and v is in m/s, when t = 0 and v = 0.

To Find: the relation between v and t.

Solution:

Integrate the time component of the equation on both sides:

∫ a dt = ∫ 6v^(1/2) dt

Evaluate the integrals:

v = 2t^3 + C

Use the initial condition when t = 0, v = 0 to find the value of C:

0 = 2(0)^3 + C

C = 0

To get the answer, substitute the value of C into the equation from step 2:

v = 2t^3

Therefore, the relation between velocity and time for the given particle motion is v = 2t^3. As time increases, the velocity of the particle increases at a rate proportional to the cube of the time elapsed.

To learn more about velocity from the given link.

https://brainly.in/question/36267867

#SPJ3