the motion of a particle of mass 'm' is described by y=ut+1/2at*2. Find the force acting on the particle.
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Answered by
202
hey there is a answer !!
I hope you help !!!!
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=>. y = ut + ½ gt2
Differentiate y with respect to t which gives velocity as dy/dt = v
dy/dt = u + ½ g (2t)
v=u + gt -------------------Eqn (1)
Differentiate v with respect to t which gives velocity as d2y/dt2 = dv/dt = a
dv/dt = 0 + g
a = g ----------------------Eqn (2)
We know that force acting on a mass m is given by F = ma
Now from Eqn (2), substitute a =g, Hence, F = mg
I hope you help !!!!
=====================
=>. y = ut + ½ gt2
Differentiate y with respect to t which gives velocity as dy/dt = v
dy/dt = u + ½ g (2t)
v=u + gt -------------------Eqn (1)
Differentiate v with respect to t which gives velocity as d2y/dt2 = dv/dt = a
dv/dt = 0 + g
a = g ----------------------Eqn (2)
We know that force acting on a mass m is given by F = ma
Now from Eqn (2), substitute a =g, Hence, F = mg
ashisingh65289:
thnx
Answered by
114
Answer: don't worry here is the answer :)
Explanation:
Thus the given equation describes the motion of a particle under acceleration due to gravity and y is the position coordinate in the direction of g
Hope it helps....
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