Question

The motion of an object of mass 5 kg is shown in the adjoining velocity-time graph of fig. find, from the graph the
(a) Acceleration,
(b) force acting on the object, and
(c) change in momentum 2s after the start.

Answer 1

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Answer 2

Ello❤❤

Here,
mass of an object, m = 5kg

From velocity-time graph, we find that initial velocity, u = 0

As the graph is a straight line, the object is uniformly accelerated to a velocity, v = 15 ms-1 in a time, t = 6s

(a) Hence,

acceleration, a = v-t/t = 15-0/6 = 2.5ms-2

(b) Hence,

force acting on the object, F = ma = 5×2.5 = 12.5 N

(c) From the graph, velocity of the object in 2s after the start, v₁ = 5 m s -¹

= m(v₁ - u) = 5 × (5 -0)
____________
⎟ = 25 kg m s-¹ ⎢
⎜___________⎢