the motorist travelled town A to B at the average speed of 54 km per hour on returning journey as average speed was 60 km per hour the total time taken is 9 1 by 2 hours find the distance between the two towns
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average speed=2 x 54 x 60/(54+60)=6480/114 time taken=9 hours
=> distance travell both way =6480/114 x 9 =511.6km
=> distance (one way) =255.78
=> distance travell both way =6480/114 x 9 =511.6km
=> distance (one way) =255.78
asmitha76:
sir your answer is wrong sir .the answer is 270
Answered by
1
Answer: x= 63
Step-by-step explanation:
Let the speed of one motorcycle1 be x.
Then motorcycle2 will be x+7 ((7 kmph faster))
AFTER TWO HOURS
Motorcycle1: 2×x
Motorcycle2: 2×x+7
2x + 2(x+7)+ 34 =300
2x + 2x+14 + 34=300
4x + 48 =300
4x= 300- 48
4x= 252
x= 252÷4
x= 63
Therefore motorcycle1 is at a speed of 63kmph while motorcycle2 is at a speed of 63+7=70 kmph.
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