Question

The movement of a force around a pivot is 80Nm . If the applied force is 30N ,how far is the pivot from the point where the force is applied?​​

Answer 1

Answer:

2.667m

Explanation:

Moment of force =Force x distance

Therefore ,

Distance= $\frac{Moment of Force}{force}$

             = $\frac{80}{30}$

             =2.667m

Answer 2

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