Physics, asked by shanviPrasad, 7 months ago

the movement of a force of 25N about a point is 2.5Nm . Find the perpendicular distance of force from that point.​

Answers

Answered by banani2112p8zd4n
4

Answer:

Torque=Force×perpendicular distance

2.5Nm=25N×perpendicular distance

2.5/25=perpendicular distance

0.1m=perpendicular distance

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Answered by AbdJr10
2

Answer:

Hope the answer will help

Explanation:

moment \: of \: force = force \times per \: distance \\2.5 = 25 \times per \: distance \\ distance = 0.1

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