Question

the multiple of 40 nearest to the greatest number of four digits is ?

Answer 1

As its multiple of 40

That is at last 0 will come

As Greatest four digit No would 99a0 which would be divisible by 40

where a we have to find

Now for no to be divisible by 4, last 2 digits should be divisible by 4

Now check for first three digits that is 99a

here last 2 digits that is "9a" should be divisible by 4

As 4× 23 = 92

4× 24 = 96

so only these these two multiples contain 9

As Greatest we have to find So take 96

So a = 6


So no is 9960

Answer 2

The required answer is 9960.