The mutual heat of neutralisation of 40gm of naoh and 60gm ch3cooh will be
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Hello Dear.
This is the neutralization reactions :-
Reaction:-
____________________________
NaOH + CH₃COOH -----→ CH₃COONa + H₂O
____________________________
Molar mass of NaOH = 40 g/mol.
Mass of NaOH = 40 g.
∵ Number of Moles = mass/molar mass
=40/40 = 1 mol
Molar mass of CH₃COOH = 60 g/mol.
Mass of CH₃COOH = 60 g.
Number of mole = 60/60 = 1 mol.
We know , NaOH is the strong base whereas CH₃COOH is a weak acid .
The amount of heat released in the neutralization of strong acid by a strong base is always 57.1 k J . but since acetic acid is a weak acid , therefore some amount of energy is utilized in ionization of acetic acid.
Thus enthalpy of neutralization is less then 57.1 K J.
Hope it Helps.
This is the neutralization reactions :-
Reaction:-
____________________________
NaOH + CH₃COOH -----→ CH₃COONa + H₂O
____________________________
Molar mass of NaOH = 40 g/mol.
Mass of NaOH = 40 g.
∵ Number of Moles = mass/molar mass
=40/40 = 1 mol
Molar mass of CH₃COOH = 60 g/mol.
Mass of CH₃COOH = 60 g.
Number of mole = 60/60 = 1 mol.
We know , NaOH is the strong base whereas CH₃COOH is a weak acid .
The amount of heat released in the neutralization of strong acid by a strong base is always 57.1 k J . but since acetic acid is a weak acid , therefore some amount of energy is utilized in ionization of acetic acid.
Thus enthalpy of neutralization is less then 57.1 K J.
Hope it Helps.
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