The n" term of an arithmetic progression is a = 4n+ 5 then the 3rd term is:
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Answer:
Third term=4(3)+5
=17
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Question :- The nth term of an arithmetic progression is an=4n+5 then the 3rd term is ?
Solution :-
we know that,
nth term of an AP = a + (n - 1)d
a = first term .
d = common difference .
so,
→ a + (n - 1)d = 4n + 5
→ a + (n - 1)d = 4n - 4 + 4 + 5
→ a + (n - 1)d = 9 + 4n - 4
→ a + (n - 1)d = 9 + (n - 1)4
comparing we get,
a = 9
d = 4
therefore,
→ a3 = a + (3 - 1)d
→ a3 = 9 + 2*4
→ a3 = 9 + 8
→ a3 = 17 (Ans.)
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