Question

The n" term of an arithmetic progression is a = 4n+ 5 then the 3rd term is:
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Answer 1

Answer:

Third term=4(3)+5

=17

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Answer 2

Question :- The nth term of an arithmetic progression is an=4n+5 then the 3rd term is ?

Solution :-

we know that,

nth term of an AP = a + (n - 1)d

a = first term .

d = common difference .

so,

→ a + (n - 1)d = 4n + 5

→ a + (n - 1)d = 4n - 4 + 4 + 5

→ a + (n - 1)d = 9 + 4n - 4

→ a + (n - 1)d = 9 + (n - 1)4

comparing we get,

a = 9

d = 4

therefore,

→ a3 = a + (3 - 1)d

→ a3 = 9 + 2*4

→ a3 = 9 + 8

→ a3 = 17 (Ans.)

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