The n(th) term of an AP is 6n+2. Find the commn difference. [ CBSCE 2008 ]
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Tn = 6n + 2
On putting n = 1 we'll get the first term.
=> T1 = 6(1) + 2
=> T1 = 8
On putting n = 2 we'll get the second term
=> T2 = 6(2) + 2
=> T2 = 14
We know that, common difference is the difference between two consecutive terms.
Thus, common difference = T2 - T1 = 14 - 8 = 6
Thus, common difference is 6.
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