The nature of graph for effect of concentration on rate of reaction between 0.1 M Na2 S2 O3 and 1 M HCL is a straight line with
Answers
Answer:
It can be observed from the given graph that t
1/2
is constant and is independent of the concentration. We know that,
t
1/2
∝(1/a
o
)
n−1
where, a
o
is the initial concentration of the reactant
n is the order of the reaction
Now for first order reaction n=1 and t
1/2
will be independent of a
o
(i.e. concentration) as depicted in the graph.
Hence, the reaction is of first order.
As,t
1/2
is independent of initial concentration , it will be same whether the concentration is 2 Mol /L or 4 Mol /L
So, n=1 and t=10 minutes (as already given in the question)
Explanation:
Answer: Increasing slope with intersecting Y-axis.
Explanation: In the reaction of 0.1 M Na2S2O3 and 1M HCl, if concentration is being increased of the reactants, it will lead to more atoms surrounding to each other. As a result, collision between the atoms increases. The increasing collision among the atoms will result into increase in the rate of the reaction. The plot between effect of concentration vs rate of the reaction, gives a straight line with a increasing slope intersecting the Y - axis.
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