Question

the nature of root of quadratic equation x^2-5x-7=0 are real and equal . find it true or false
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Answer 1

Answer:

false

it has two distinct and real roots

Answer 2

$Compare \: given \: Quadratic \: equation$

$x^{2}-5x-7 = 0 \:with \: ax^{2}+bx+c=0 , we \:get$

$a = 1 , \: b = -5 \:and \: c = -7$

$Discriminant (D) = b^{2} - 4ac$

$= (-5)^{2} - 4 \times 1 \times (-7)$

$= 25 + 28$

$= 53$

$\gt 0$

$\therefore \blue {Roots \: are \: real \: and \: distinct }$

$\red{ Given \: statement \: is \: false }$

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