Question

The nature of roots of quadratic equation x^2-5x-7=0 are real and equal

Answer 1

Answer:

yes the nature of roots is real and equal.

Step-by-step explanation:

1) To find the nature of roots the formula D⇒b^2-4ac=0

so x^2-5x-7 is the equation so,

D⇒(-5)^2-4(-7)(1)=0

D⇒25-4(-7)=0⇒25-24⇒1.

If the value of D is more than 0 the nature of the roots is said to be real and equal.

HOPE THIS WILL HELP YOU

Answer 2

Answer:

false

real and distinct(unequal)

Step-by-step explanation:

Nature of roots of any quadratic equation is determined by the value under root or discriminant of that equation.

Discriminant of ax² + bx + c = 0 is b²- 4ac.  On comparing:

a = 1,   b = -5,   c = - 7

∴ discriminant = (-5)² - 4(1)(-7)

                        = 25 + 28

                        = 53

As the discriminant > 0, roots are real and irrational(and different).