Physics, asked by Terabaap8420, 1 year ago

The near point of a hypermetropic eye is 50cm. What is the narure and power of the lens required to enable him to tead abook placed at 25 cm from the eye?

Answers

Answered by riameena152944
0

for a hypermetropic eye u=-25cm and v=-50cm

substituting in the lens formula we get focal length is f=50cm =0.5m

from the formula P=1/f

P=1/0.5  2D

so the power of the lens is 2 dioptre and the nature of lens is a converging lens or a convex lens

pls mark it as brainlist

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