the near point of a person is at 75 cm from his eye. find the power of lens which he requires to read clearly a book held at a distance of 25 cm from the eye
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3
1/0.75=4/3
=1.33 hoga right answer
=1.33 hoga right answer
Answered by
8
1/f = 1/v - 1/u
f = focal length, v = image distance = -75 (in this case) & u= object distance = -25 (in this case)
therefore, (1/-75) - (1/-25) = 1/f
⇒ -1/75 - (-1/25) =1/f
⇒ -1+3/75 = 1/f
⇒2/75 = 1/f
∴ f = 75/2 = 37.5 cm = 0.375 m
Power of lens, 'P' = 1/f (f in meters)
⇒ P = 1/0.375 = + 2.66 D
sareenamuneer:
is it right
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