Question

The near point of the hypermetropic eye is 0.9 what is the nature and the power of the lens required to correct the defect

Answer 1

Hypermetropia is a condition of the eye where the person is not able to see things clearly when nearer to the eye. The normal near point of the eye is 25 cm , i.e. for normal individuals to see clearly, an object must be at a distance of atleast 25 cm. For a hypermetropic eye with a near point of 1m (100 cm), to see an object placed at 25 cm, the virtual image needs to be for med at 100 cm.

Answer 2

Answer:far point of a hypermetropic eye( v)= -1m

near point (u)=-25cm

using lens formula

1/v - 1/u = 1/f

1/-100 - 1/-25 = 1/f

5 1

------------------ = -----------'

100 20

f=20 cm

1m=100cm

=0.2m

D =1/0.2

=5

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