Question

the net electric flux through a cube of side 1 m kept in uniform electric field E= 10^4 N/C is

Answer 1

Answer:

Gauss Law:

The net electric flux through a closed surface is $\dfrac{1}{ \varepsilon_{0} }$ times the net charge enclosed by the surface.

• Uniform Electric Field (E) = 10⁴ N/C

• Side of cube = 1 m

$\longrightarrow \sf \phi_{(closed)} = \dfrac{q_{(net \: inside)}}{ \varepsilon_{0} }$

$\longrightarrow \displaystyle \sf \oint \overrightarrow{E}.d\overrightarrow{A}= \dfrac{q_{(net \: inside)}}{ \varepsilon_{0} }$

• The charge inside the cube is not provided, therefore net charge will be considered as 0.

$\longrightarrow \displaystyle \sf \oint \overrightarrow{E}.d\overrightarrow{A}= \dfrac{0}{ \varepsilon_{0} }$

$\longrightarrow \displaystyle \sf \oint \overrightarrow{E}.d\overrightarrow{A}= 0$

$\longrightarrow \underline{ \boxed{ \red{ \bf \phi_{(closed)} = 0}}}$