Question

The new no. of polynomials having zeroes as -2 and 5 is........​

Answer 1

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$<marquee behaviour= "slide" direction="down"$ANSWER:

$<marquee behaviour= "slide" direction="down"$ANSWER: d) more than 3

$<marquee behaviour= "slide" direction="down"$ANSWER: d) more than 3EXPLANATION:

$<marquee behaviour= "slide" direction="down"$ANSWER: d) more than 3EXPLANATION:

$<marquee behaviour= "slide" direction="down"$ANSWER: d) more than 3EXPLANATION: THE POLYNOMIALS WITH ZEROES -2 AND 5 IS;

$<marquee behaviour= "slide" direction="down"$ANSWER: d) more than 3EXPLANATION: THE POLYNOMIALS WITH ZEROES -2 AND 5 IS;

$<marquee behaviour= "slide" direction="down"$ANSWER: d) more than 3EXPLANATION: THE POLYNOMIALS WITH ZEROES -2 AND 5 IS; f(x)=x²-(-2+5)x+(-2)5

$<marquee behaviour= "slide" direction="down"$ANSWER: d) more than 3EXPLANATION: THE POLYNOMIALS WITH ZEROES -2 AND 5 IS; f(x)=x²-(-2+5)x+(-2)5 =f(x)=x²-3x-10

$<marquee behaviour= "slide" direction="down"$ANSWER: d) more than 3EXPLANATION: THE POLYNOMIALS WITH ZEROES -2 AND 5 IS; f(x)=x²-(-2+5)x+(-2)5 =f(x)=x²-3x-10BUT AS WE CAN MULTIPLY THIS POLYNOMIAL WITH ANY OTHER NUMBER,

$<marquee behaviour= "slide" direction="down"$ANSWER: d) more than 3EXPLANATION: THE POLYNOMIALS WITH ZEROES -2 AND 5 IS; f(x)=x²-(-2+5)x+(-2)5 =f(x)=x²-3x-10BUT AS WE CAN MULTIPLY THIS POLYNOMIAL WITH ANY OTHER NUMBER, THE NO. OF POLYNOMIALS HAVING ZEROES -2 AND 5 CAN BE INFINITE

Answer 2

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Let p (x) = ax2 + bx + c be the required polynomial whose zeroes are -2 and 5. Hence, the required number of polynomials are infinite.

Thanks.