Question

The newspaper in Haventown had a circulation of 80,000 papers in the year 2000. In 2010, the circulation was 50,000. With x=0 representing the year 2000, the graph below models this scenario. A coordinate plane showing Newspaper Circulation, Years Since 2000 on the x-axis and Circulation on the y-axis. A line starting at (0, 80,000), passing through a point at (10, 50,000) and ending at (18, 25,000). What number will complete the point-slope equation that models this scenario? y−50,000=[_______](x−10)
−3,000
−2,000
2,000
3,000

Answer 1

Answer:

A. -3,000

Step-by-step explanation:

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Answer 2

The number - 3000 will complete the point-slope equation that models this scenario

Given :

• The newspaper in Haventown had a circulation of 80,000 papers in the year 2000.
• In 2010, the circulation was 50,000.
• With x = 0 representing the year 2000, the graph below models this scenario.

To find :

The number will complete the point-slope equation that models this scenario

y − 50,000 = [_______] (x−10)

−3,000

−2,000

2,000

3,000

Solution :

Step 1 of 3 :

Write down the points through which the line passes through

The line is passing through a point at (0, 80000) and (10, 50000)

Step 2 of 3 :

Find the slope of the line

Since the line is passing through the point (0, 80000) and (10, 50000)

So slope of the line

= m

$\displaystyle \sf{ = \frac{80000 - 50000}{0 - 10} }$

$\displaystyle \sf{ = \frac{30000}{ - 10} }$

$\displaystyle \sf{ = - 3000 }$

Step 3 of 3 :

Find the number that will complete the point-slope equation that models this scenario

The required point-slope equation that models this scenario is

$\sf y - y_1 = m(x - x_1)$

$\displaystyle \sf{ \implies } y -50000= - 3000(x - 10)$

Hence the required number is - 3000 which will complete the point-slope equation that models this scenario

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