Question

the ninth term is equals to 6 times it's second term and its 5th term is 22 find AP​

Answer 1

Solution:

$a_{9} = 6( a_{2} ) \\ a + 8d = 6a + 6d \\ 2d = 5a$

now,

$a_{22} = a + 21d \\ = \frac{2d}{5} + 21d \\ = \frac{2d + 105d}{5} \\ =$