Two objects, one 4 times as massive as the other, are approaching each other under their mutual gravitational
attraction. When the separation between the objects is 100 km, the acceleration of the lighter object is 1 m/
s2. When the separation between them is 25 km, the acceleration of the heavier object is
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Answer:
Given,
Mass ofthe first body x4 =mass of the
second body.
Let the acceleration of the body be a
AS per law gravitation,
GMm
F
=
F
GM
a Atr = 100km, 1 ==
m
=>
(100)
G=1. 100)3
M
F
Atr 25Cm, M(25
Gm
4m/s2
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