The ninth term of an A.P is - 32 and the sum of its eleventh and thirteenth term is - 94. Find the common difference of the A.P .
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Answered by
18
Answer:
Step-by-step explanation:
Let the first term be a and common diference be d.
Ninth term= a+8d= -32........(i)
Sum of 11th and 13th term is -94 ∴ a+10d+a+12d=-94
or,2a+22d=-94
or,a+11d=-47..........(ii)
(ii) - (i) ⇒a + 11d - a - 8d = -47 + 32
⇒3d = -15
⇒d = -5
∴common difference = -5
Answered by
3
nth term=a + (n-1)d
therefore, n11=a + 10d
n13=a + 12d
therefore, n11=a + 10d
n13=a + 12d
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