Question

The no. Of atoms present in 0.5 g atoms of nitrogen is as same as the atoms in

Answer 1

hii dear!!
here ur answer!!
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▪Solution :
Atomic mass of nitrogen =14g

▪Therefore , mass of 1 mole of nitrogen

=14g
=14g
Now, 1 more

=6.022×10ki power 23 atoms

=6.022×10 ki power 23 atoms

▪Since,

1g−atom=1
1g−atom=1
more

0.5g−atom=0.5moles
0.5g−atom=0.5moles

▪Therefore no of atoms in 0.5 moles of Nitrogen:-

=6.022×10 ki power23×0.5

=6.022×1023×0.5=3.011×10 ki power23

=3.011×1023

Now,
12g
12g

><Carbon =1 mole carbon

32g
32g
sulphur = 1 mole sulphur
8g
8g
oxygen =0.5 mole oxyen

24g
24g

><magnesium =1 mole magnesium

>>>Number of atoms in 0.5 mole oxygen
=3.011×10 ki power 23

=3.011×10 ki power 23

hope help u g ☺☺
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