Question

the no. of chocolate with A and B are in ration 3:5 .If A gets 8 from his mother tha ration becomes 4:5 . find the no. tgat A& B had initially​

Answer 1

Answer:

The number of chocolates with A and B initially are  24 and 40 respectively

Step-by-step explanation:

Given,

The number of chocolates with A and B is in the ratio of 3:5

A receives 8 chocolates from his mother, then the new ratio is 4:5

To find,

The number of chocolates with A and B initially

Solution

Since the ratio of chocolates with A and B is 3:5.

The number of chocolates with A = 3x

The number of chocolates with B = 5x

After receiving 8 chocolates from mother

The number of chocolates with A = 3x +8

The number of chocolates with B = 5x

Since the new ratio is 4:5 we have

3x+8 : 5x = 4:5

$\frac{3x+8}{5x} = \frac{4}{5}$

5(3x+8) = 4×5x

15x +40 = 20x

5x = 40

x = $\frac{40}{5}$ =8

∴ The number of chocolates with A initially = 3x = 3×8 = 24

The number of chocolates with B initially = 5x = 5×8 = 40

The number of chocolates with A and B initially are  24 and 40 respectively

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