Question

the no of electron present in 1.2g o2​

Answer 1

Answer:

192.70×10²²

Explanation:

1gram oxygen contains 6.022×10²²molecules

therefore 32 will contain ?

cross multiply.

32×6.022×10²²=192.70×10²²

Answer 2

Answer : The number of electrons present in 1.2 g of $O_2$ is $36.16\times 10^{22}$ protons.

Solution : Given,

Mass of $O_2$ = 1.2 g

Molar mass of $O_2$ = 32 g/mole

First we have to calculate the moles of $O_2$.

$\text{Moles of }O_2=\frac{\text{Mass of }O_2}{\text{Molar mass of }O_2}=\frac{1.2g}{32g/mole}=0.0375moles$

Now we have to calculate the molecules of $O_2$.

1 mole of $O_2$ has $6.022\times 10^{23}$ molecule of $O_2$

0.0375 moles of $O_2$ has $0.0375\times 6.022\times 10^{23}=2.26\times 10^{22}$ molecule of $O_2$

Now we have to calculate the number of electrons in $O_2$.

The number of electrons present in 1 molecule of $O_2$ is,

$O_2$ = 2(8) = 16 protons

Number of electrons present in 1 molecule of $O_2$ = 16

Number of electrons present in $2.26\times 10^{22}$ molecule of $O_2$ = $16\times 2.26\times 10^{22}=36.16\times 10^{22}$ electrons

Therefore, the number of electrons present in 1.2 g of $O_2$ is $36.16\times 10^{22}$ electrons.