Question

The no. of electrons in 1.6g of ch4 is approximately

Answer 1

16 g of CH4 contains Na atoms i.e 6.023×10^23 atoms and each atom contain 10 electrons.....so 1.6 g will contain = (1.6 × 10 × 6.023×10^23)÷16
= 6.023× 10^23 electrons