Question

The no of moles in 4*10 POWER 31 atom s iron are

Answer 1

no of mole= gn no of atom/na

=4*10^31/6*10^23

Answer 2

There are $6.64 \times 10^{7}$ mol present in $4 \times 10^{31}$ atoms.

Explanation:

It is known that there are $6.022 \times 10^{23}$ atoms present in every mole of a substance. It is given that number of atoms present in iron are $4 \times 10^{31}$ atoms.

Hence, calculate the number of moles present in $4 \times 10^{31}$ atoms as follows.

             $\frac{4 \times 10^{31}atom}{6.022 \times 10^{23} atom/mol}$

              = $0.664 \times 10^{8}$ mol

or,          = $6.64 \times 10^{7}$ mol

Therefore, we can conclude that there are $6.64 \times 10^{7}$ mol present in $4 \times 10^{31}$ atoms.

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