Question

The no. of moles of KClO3 that will give 6 moles of oxygen.
Please describe complete process...​

Answer 1

KClO₂ ----(On heating with MnO2 [Catalyst])----> 2KCl + 3O₂

From the above reaction. its clear that

3 moles of O₂ is given out, when 2 moles of KClO₃ decomposes.

6 moles of O₂ is given out, when (x) moles of KClO₃ decomposes.

So,

x = 6 × 2 / 3

 

 = 4 moles.

Therefore, 4 moles of KClO₃ will be required to give 6 moles of Oxygen.

Answer 2

2KClO3 = 2KClO + 3 O2

so...3 moles of o2 is oobtained from 2 moles of KClO3

so....6 moles of o2 is obtained from (2*6)/3 moles oof KClO3

= 4 moles of KClO3

sorry for being late....hope it helps