the no of pens in three different pencil boxes in the ratio1:2:3.find the ratio in which the number of pens in the first and the second boxes must be increased so that the new ratio become 3:2:1
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Answer:
the no. increase in the ratio 8:4:0
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2:1 is the ratio in which the number of pens in the first and the second boxes.
Step-by-step explanation:
Let the no. of pens in three different pencil boxes be
1st box = x
2nd box = 2x
3rd box = 3x
_as the given ratio is 1:2:3
let The requires no. of pens increased to
1st box = 3y
2nd box = 2y
3rd box = y
∵ Quantity remains the same in 3rd pencil box
∴ 3x = y
⇒ x = y/3
and if x = y/3
then 2x = 2y/3
3x = y
i.e y/3, 2y/3, y
Increment in the 1st box = 3y - x
= 3y - (y/3)
= 8y/3
Increment in the 2nd box = 2y - 2x
= 2y - 2(y/3)
= 2(y - y/3)
= 4y/3
The ratio of 1st: 2nd = 8y/3 : 4y/3
=2:1
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