the no. of photons of light of wavelength 7000Å equivalent to 1J are ?
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Answered by
32
hey here is your answer
E=hc/wavelength
=6.626×10^-34Js×3×10^8/7000×10^-10m
=2.8397×10^-19J
so no of photon=1/2.8398×10^-19
=3.5214×10^18
E=hc/wavelength
=6.626×10^-34Js×3×10^8/7000×10^-10m
=2.8397×10^-19J
so no of photon=1/2.8398×10^-19
=3.5214×10^18
theemperor10:
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Answered by
0
Answer:
Energy, E=
λ
hc
Energy of a single photon of wavelength 7000 Angstrom is
7000×10
−10
hc
put h=6.6×10
−34
Joule−second and c=3×10
8
m/s
we get energy of a single photon as E=2.829×10
−19
Joule
Number of photon in 1 Joule=
E
1J
=3.52×10
18
Explanation:
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