Question

the no.of solutions of 2x+4y-6=0 and 4x+8y-12=0​

Answer 1

2x+4y-6=0------(1)

4x+8y-12=0----(2)

from these two equation

2/4=4/8=6/12

=1/2

hence these two equation have one solution

I think this will help you

Answer 2

Step-by-step explanation:

2x+4y -6=0 (1)

4x+8y-12=0 (2)

x y 1

b1 c1 a1 b1

b2 c2 a2 b2

4 -6 2 4

8 -12 4 8

$\frac{x}{b1c2 - b2c1} = \frac{y}{c1a2 - c2a1} = \frac{1}{a1b2 - a2b1}$

$\frac{x}{(4)( - 12) - (8)( - 6) } = \frac{y}{( - 6)(4) - ( - 12)(2)} = \frac{1}{(2)(8) - (4)(4)}$

$\frac{x}{0} = \frac{y}{0} = \frac{1}{0}$

$\frac{x}{0} = \frac{1}{0}$

$x = 0$

$\frac{x}{ - 48 + 48 } = \frac{y}{ - 24 + 24} = \frac{1}{16 - 16}$