the no. of terms in expansion (a+b+c)^9
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Answered by
2
hai,
For expansion of (a+b+c)^n has
(n+1)(n+2)/2 terms
here n=9
so (9+1)(9+2)/2
therefore 10*11=110/2
=55 terms
hope helped :)
For expansion of (a+b+c)^n has
(n+1)(n+2)/2 terms
here n=9
so (9+1)(9+2)/2
therefore 10*11=110/2
=55 terms
hope helped :)
pipi:
thanks
Answered by
1
use formula,
( a + b + c)ⁿ
then no of terms = (n+1)(n+2)/2
then
n = 9
no of terms = (9+1)(9+2)/2 = 55
( a + b + c)ⁿ
then no of terms = (n+1)(n+2)/2
then
n = 9
no of terms = (9+1)(9+2)/2 = 55
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