The no.of unit cell in 1m3 of fcc nickel is (radius of nickel is 1.243 angstrom )
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Answer:2.3×10^28
Explanation:
Answered by
0
Answer:
The no.of unit cell in 1m3 of fcc nickel is 1.22×10³².
Explanation:
Given : Radius of nikel = 1.243 Angstrom
volume of nikle = 1m³
Now for Fcc nikle the realtion between the radius and lattice constant is
r= radius of the atom
a= latiice constant
so we cal calculate lattice constant from above
now volume of lattice cell = a³
volume = (4.35)³ × (10⁻³⁰)
Now number of unit cell =
Hence the Number of unit cell in 1m³ sample is 1.22×10³².
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