Math, asked by legend25, 1 year ago

the no. terms in the expansion of (x+a)^100+(x-a)^100 after simplification is:

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Answered by Anonymous
12
this is ur required result
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Answered by amitnrw
8

Total number of terms = 51  in the expansion of (x + a)¹⁰⁰   + (x - a)¹⁰⁰

Step-by-step explanation:

(x + a)¹⁰⁰   + (x - a)¹⁰⁰

(x + a)¹⁰⁰  = x¹⁰⁰   + ¹⁰⁰C₁x¹⁰⁰⁻¹a¹   +...........+ ¹⁰⁰Cₙ x¹⁰⁰⁻ⁿaⁿ +.................¹⁰⁰C₁₀₀x⁰a¹⁰⁰

(x - a)¹⁰⁰  = x¹⁰⁰   + ¹⁰⁰C₁x¹⁰⁰⁻¹(-a)¹   +..........+ ¹⁰⁰Cₙ x¹⁰⁰⁻ⁿ(-a)ⁿ +...............¹⁰⁰C₁₀₀x⁰(-)a¹⁰⁰

Adding Both  ¹⁰⁰Cₙ x¹⁰⁰⁻ⁿaⁿ +  ¹⁰⁰Cₙ x¹⁰⁰⁻ⁿ(-a)ⁿ  = 0  for  n = odd

n = 1  , 3 , 5 ..................................., 97 , 99  = 50 Terms

 ¹⁰⁰Cₙ x¹⁰⁰⁻ⁿaⁿ +  ¹⁰⁰Cₙ x¹⁰⁰⁻ⁿ(-a)ⁿ  = 2  ¹⁰⁰Cₙ x¹⁰⁰⁻ⁿaⁿ  for  n = Even

n = 0 , 2 , 4 , .................................., 98 , 100  = 51 Terms

(x + a)¹⁰⁰   + (x - a)¹⁰⁰ = 2(x¹⁰⁰   + ¹⁰⁰C₂x¹⁰⁰⁻²a²   +...........+ ¹⁰⁰C₂ₙ x¹⁰⁰⁻²ⁿa²ⁿ +.................¹⁰⁰C₁₀₀x⁰a¹⁰⁰)

Total number of terms = 51

Total number of terms = 51  in the expansion of (x + a)¹⁰⁰   + (x - a)¹⁰⁰

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