the normal at the point (1,2) on the curve 2y+x^2=5 is:
a.x-y+1=0
b. x-y=0
c. x+y+1=0
d. xy=1
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2y'+2x=0
y'=-x
y'=-1
slope of normal line is 1
then equation of normal passing through (1,2)is
y-2=1(x-1)
x-y-1+2=0
x-y+1=0
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