Math, asked by MrInayat, 10 months ago

the normal at the point (1,2) on the curve 2y+x^2=5 is:
a.x-y+1=0
b. x-y=0
c. x+y+1=0
d. xy=1​

Answers

Answered by rahman786khalilu
0

2y'+2x=0

y'=-x

y'=-1

slope of normal line is 1

then equation of normal passing through (1,2)is

y-2=1(x-1)

x-y-1+2=0

x-y+1=0

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