Question

The normal boiling point of water is 373K. Vapor Pressure of water T is 19mm Hg. If Enthalpy of Vaporization is 40.67KJ/mol, Then temperature T would be???​

Answer 1

see if u remember the formula guvenin ncert.

P1T1 = P2T2

P1 = 760 mm Hg and T1 = 373K

we get T = 291K