The Normality of 0.1 M solution of H3PO4 is
Answers
Answered by
69
Normality =molarity×n -factor
And for any phosphorus containing
acid ,n-factor =(no.of o-atoms-1)=(4-1)
=3.
Molarity =0.1M
NORMALITY=0.1×3=0.3N
Hope it helps
And for any phosphorus containing
acid ,n-factor =(no.of o-atoms-1)=(4-1)
=3.
Molarity =0.1M
NORMALITY=0.1×3=0.3N
Hope it helps
Answered by
1
Given: Molarity of H₃PO₄ = 0.1 M
To Find: Normality of H₃PO₄ = N=?
Solution:
Formula used:
- Normality=Molarity × Number of equivalent H or acidity
- 3 H atoms present hence acidity = 3
Applying the above Formula
N = 0.1 × 3
N = 0.3N
Hence, Normality of 0.1 M solution of H₃PO₄ = 0.3N
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