Question

The normality of 10% (w/v)h2s04 solution is nearly

Answer 1

Answer:

50N

Explanation:

Normality = (w/v) × 10 ÷ GEW of H2SO4

given ,

(w/v) = 10

GEW of H2SO4 = 2

hence,

Normality = (w/v) × 10 ÷ GEW of H2SO4

= 10×10÷2

= 50 N

therefore ,

Normality = 50 N