Question

the normality of 1M H3PO3 solution is

Answer 1

Normality = mass/eq.mass x 1000/volume of solutions( ml)

Morality = mass/ molar mass x 1000/ volume of solution (ml) 

and Eq. mass = Molar mass/ n factor

or normality = Mass/ molar mass/ n factor  x 1000/ volume of solution (ml) = mass/molar mass x 1000/ volume of solution (ml) x n factor = molarity x n factor

For H3PO4, n = 3 

So normality = 1x3 = 3N

Answer 2

Answers

Normality = mass/eq.mass x 1000/volume of solutions( ml)

Morality = mass/ molar mass x 1000/ volume of solution (ml)

and Eq. mass = Molar mass/ n factor

or normality = Mass/ molar mass/ n factor x 1000/ volume of solution (ml) = mass/molar mass x 1000/ volume of solution (ml) x n factor = molarity x n factor

For H3PO3, n = 2

So normality = 1x2=2