the nth term of 3,7,11,15..........is
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tn=a+(n-1)d
tn= 3+(n-1)×4
tn=3+4n-4
tn=4n-1
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Answer:
3n
d=3
a=3
n=nth
an=a+(n-1)×d
an=3+(n-1)4
an=3+4n-4
an=-1+4n
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