Question

the nth term of an AP, The sum of whose n terms is Sn is
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Answer 1

Answer:

Sn = n/2 [2a + (n - 1)d]

Step-by-step explanation:

Answer 2

Answer:

we know, difference between two consecutive terms of an arithmetic progression (AP) must be same.

e.g., if a is the first term and d is the common difference of an AP.

then, series is : a , a + d , a + 2d , a + 3d , a + 4d...... are in AP

now, nth term = T_nT

n

= a + (n - 1)d

sum of n terms = S_nS

n

= a + (a + d) + (a + 2d) + ..... + [a + (n - 1)d]

= (a + a + a ....n times ) + [d + 2d + 3d + .... + (n - 1)d ]

= na + d[1 + 2 + 3 + ..... + (n -1)]

= na + d[(n - 1)(n)/2 ]

= n/2 [ 2a + (n - 1)d]

hence, S_nS

n

= n/2 [2a + (n - 1)d ]

Step-by-step explanation:

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