The nth term of an arithmetic progression is 1/2(3n - 15).
Find the value of n for which the sum of the first n terms is 84.
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Step-by-step explanation:The given progression 9, 15, 21, 27, ... .
Clearly, 15 − 9 = 21 − 15 = 27 − 21 = 6 (Constant)
Thus, each term differs from its preceding term by 6. So, the given progression is an AP.
First term = 9
Common difference = 6
Next term of the AP = 27 + 6 = 33
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