Math, asked by snehasagar146, 8 hours ago

the nth term of an arithmetic progression is given by an =7-4n then the common difference is​

Answers

Answered by 1157684
53

Answer:

Tn = 7 −4n

T 1 = 7 − 4 (1) = 3, T2 = 7 − 4 (2) = −1, T3 =7−4 (3) = −5

d = T3 −T2 = T2 −T1

=−5−(−1)=−1−3

d=−4=−4

Common difference =−4.

Answered by aleenaakhansl
0

Answer:

-4 is the common difference.

Step-by-step explanation:

If the nth term is given ,

we need to put

n=1,2,3....

to get out the first , second and third term .

  • Frist term: =7-4(1)

=7-4=3

  • Second term=7-4(2)

=7-8=-1

  • Third term=7-4(3)

=7-12=-5

hence, we got our 3 terms of the A.P.,

that is - (3,-1,-5) .

so from here we can find out the common difference.

common difference= second term - first term

= -1 - 3

= -4

checking, C.D= third term- second term

=-5 -(-1)

= -5+1

=-4

hence , -4 is the common difference.

(#SPJ3)

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