the nth term of an arithmetic progression is given by an =7-4n then the common difference is
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Answered by
53
Answer:
Tn = 7 −4n
T 1 = 7 − 4 (1) = 3, T2 = 7 − 4 (2) = −1, T3 =7−4 (3) = −5
d = T3 −T2 = T2 −T1
=−5−(−1)=−1−3
d=−4=−4
Common difference =−4.
Answered by
0
Answer:
-4 is the common difference.
Step-by-step explanation:
If the nth term is given ,
we need to put
n=1,2,3....
to get out the first , second and third term .
- Frist term: =7-4(1)
=7-4=3
- Second term=7-4(2)
=7-8=-1
- Third term=7-4(3)
=7-12=-5
hence, we got our 3 terms of the A.P.,
that is - (3,-1,-5) .
so from here we can find out the common difference.
common difference= second term - first term
= -1 - 3
= -4
checking, C.D= third term- second term
=-5 -(-1)
= -5+1
=-4
hence , -4 is the common difference.
(#SPJ3)
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