The nth term of arithmetic sequence is 8n-4 prove that the sum of first n term is a perfect square?
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Step-by-step explanation:
nth term of sequence tn = 8n - 4
1st term of sequence t1 = 8(1) - 4
t1 = 4
sum of n terms = n/2 [ t1 + tn ]
sum of n terms = n/2 [ 4 + 8n - 4 ]
sum of n terms = n/2 [ 8n ]
sum of n terms = 4n^2
which is the perfect square
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