Math, asked by mohajaarias, 1 year ago

THE NTH TERM OF THE SERIES 1+ 1+2/2 + 1+2+3/3 + ... IS n-1/2 n 2 +1/2 n+1/2 n 2 -1/2

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Answered by kvnmurty
2
The question is not clear... see the answer...

S_n=1+\frac{1+2}{2}+\frac{1+2+3}{3}+......\\\\T_n=\frac{1+2+3+...+n}{n}=\frac{n+1}{2}\\\\S_n=\Sigma_{n=1}^N\ [ \frac{n+1}{2} ]=\frac{1}{2}[\Sigma\ n+\Sigma\ 1]\\\\=\frac{1}{2}[\frac{n(n+1)}{2} +n]=\frac{n^2+3n}{4}
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