Chemistry, asked by sachinsamal231, 2 months ago

. The nucleus of an atom is discovered by the scientist:
O (A) Neil's Bohr
O (B) Rutherford
(C) Einstein
O (D) Goldstein​

Answers

Answered by Anonymous
2

Explanation:

LARGE[\bfſlunderlin e[\underline[GIVEN-X/ tex]\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ [tex]sf bullet \ \ \dfrac{(1+sinA cosAY 2}(1+sinA+cosA)^2}/tex]\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ [tex]LARGE[\bf\underline underline(SOLUTION:-)! tex]\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ LHS:\ \textless \ br /\ \textgreater \ [tex]sf \to \dfrac{(1+sinA-cosA)^2) (1+sinA+cosA)^2]

Expand the fractions using.

isf \to \dfrac{{cos^2-2s incostsin 2-2cos-2sin+1)] (lcos 2+2 sincostsin 2+2cos+2sin+1)]

Rearrange the terms.

\sf \to \dfrac{(cos^2+si n2-2sincos-2cos+2sin+1) [(cos"2+sin^2+2sincos+2cos+2sin+

Answer:

LARGE[\bfſlunderlin e[\underline[GIVEN-X/ tex]\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ [tex]sf bullet \ \ \dfrac{(1+sinA cosAY 2}(1+sinA+cosA)^2}/tex]\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ [tex]LARGE[\bf\underline underline(SOLUTION:-)! tex]\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ LHS:\ \textless \ br /\ \textgreater \ [tex]sf \to \dfrac{(1+sinA-cosA)^2) (1+sinA+cosA)^2]

Expand the fractions using.

isf \to \dfrac{{cos^2-2s incostsin 2-2cos-2sin+1)] (lcos 2+2 sincostsin 2+2cos+2sin+1)]

Rearrange the terms.

\sf \to \dfrac{(cos^2+si n2-2sincos-2cos+2sin+1) [(cos"2+sin^2+2sincos+2cos+2sin+

Answered by jaikishore65
6

OPTION (b)

RUTHERFORD IS THE CORRECT ANSWER

HE FOUND IT BY ALPHA-SCATTERING EXPERIMENT...

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