Question

The nucleus of an element undergoes a decay if q value of the reaction is 5.5

Answer 1

Answer:

Applying law of conservation of linear momentum and using the energy released

Velocity of \alpha α -particle and daughter nucleus is

Therefore, the kinetic energy of \alpha α particle

E=\dfrac{220-4}{220}\times 5.4 E=

220

220−4

×5.4

E=5.4\,Mev E=5.4Mev

Hence, the kinetic energy is 5.4 Mev